Given an array of integers nums
and an integer target
, return indices of the two numbers such that they add up to target
.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Example 1:
Input: nums = [2,7,11,15], target = 9 Output: [0,1] Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
Example 2:
Input: nums = [3,2,4], target = 6 Output: [1,2]
Example 3:
Input: nums = [3,3], target = 6 Output: [0,1]
Constraints:
- 2 <= nums.length <= 104
- -109 <= nums[i] <= 109
- -109 <= target <= 109 Only one valid answer exists.
Solution
class Solution {
func twoSum(_ nums: [Int], _ target: Int) -> [Int] {
var map: [Int : Int] = [:]
for (index, value) in nums.enumerated() {
if let value2 = map[target - value] {
return [index, value2]
}
map[nums[index]] = index
}
return [0, 0]
}
}